question
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| We all make mistakes, let's move on.
(don't take this too seriously, no fancy hacking skill is required at all)
This task is based on real event
Thanks to dhmonkey
hint : operator priority
ssh mistake@pwnable.kr -p2222 (pw:guest)
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题目要求我们使用ssh登录到服务器上ssh mistake@pwnable.kr -p2222，密码是guest,有的时候可能有身份的校验，这个时候需要加上参数-o StrictHostKeyChecking=no进行登录
mistake.c
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| #include <stdio.h>
#include <fcntl.h>
#define PW_LEN 10
#define XORKEY 1
void xor(char* s, int len){
int i;
for(i=0; i<len; i++){
s[i] ^= XORKEY;
}
}
int main(int argc, char* argv[]){
int fd;
if(fd=open("/home/mistake/password",O_RDONLY,0400) < 0){
printf("can't open password %d\n", fd);
return 0;
}
printf("do not bruteforce...\n");
sleep(time(0)%20);
char pw_buf[PW_LEN+1];
int len;
if(!(len=read(fd,pw_buf,PW_LEN) > 0)){
printf("read error\n");
close(fd);
return 0;
}
char pw_buf2[PW_LEN+1];
printf("input password : ");
scanf("%10s", pw_buf2);
// xor your input
xor(pw_buf2, 10);
if(!strncmp(pw_buf, pw_buf2, PW_LEN)){
printf("Password OK\n");
system("/bin/cat flag\n");
}
else{
printf("Wrong Password\n");
}
close(fd);
return 0;
}
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analyse
只是两次输入异或操作然后比较？
输入0000000000再输入11111111111即可
get flag
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| mistake@ubuntu:~$ ./mistake
do not bruteforce...
0000000000
input password : 1111111111
Password OK
Mommy, the operator priority always confuses me :(
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flag：Mommy, the operator priority always confuses me :(
